2014年7月11日 星期五

maven學習 八 ： 使用 Eclipse Maven Plugin 建立Web Project


Step1.  

  • File > New >  Maven Project
Step2 .
  • Check：
                   1.  Create a simple project (skip archetype selection)

                       2. Next

Step3. 
  • Group Id ：   tw.com.ocean      //輸入你想要的   "名稱空間"Artifact Id：  MyWebProject    //輸入你想要的   "專案名稱"Packaging：  war          


  • Finish

Step4.  設定運行環境
  • 在專案上，
       滑鼠右鍵  > Properties   > Project Facets

       Dynamic Web Module  2.5    (3.0 是 tomcat7)
       java                               1.7    (JDK 版本)
       javaScript                      1.0



          
  •   Runtimes 選擇 tomcat6



Step5.  建立 Servlet
  • 在java Resources上，滑鼠右鍵  >  New > Servlet



  • 輸入Servlet 名稱，這裡用Controller作為範例。




  Note：執行此步驟後，Eclipse會在  /ProjectD/src/main/webapp中建立
               ●   WEB-INF
               ●    web.xml 


<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns="http://java.sun.com/xml/ns/javaee" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
  <display-name>ProjectD</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
</web-app>


Step6 . 建立 index.jsp 檔
<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
  Hello !!!!  
</body>
</html>


Step7.  修改web.xml 檔

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
  <display-name>ProjectD</display-name>
 
  <servlet>
    <description></description>
    <display-name>Controller</display-name>
    <servlet-name>DispatcherServlet</servlet-name>
    <servlet-class>Controller</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>DispatcherServlet</servlet-name>
    <url-pattern>/*</url-pattern>    
  </servlet-mapping> 
  
  <servlet>
  <servlet-name>homeJSP</servlet-name>
  <jsp-file>/index.jsp</jsp-file> 
  </servlet>
  <servlet-mapping>
    <servlet-name>homeJSP</servlet-name>
    <url-pattern>/hello</url-pattern>
  </servlet-mapping>  
</web-app>


Step8.  修改Controller.java 檔

import java.io.IOException;

import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class Controller
 */
public class Controller extends HttpServlet {
private static final long serialVersionUID = 1L;
       
    /**
     * @see HttpServlet#HttpServlet()
     */
    public Controller() {
        super();
    }

/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request,response);
}

/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println("Post");
RequestDispatcher dispatcher = request.getRequestDispatcher("/hello");
}

}

Step 9.   Run  on  Server  
  • 執行專案後，將導向Controller.java ，在導向index.jsp

下一篇將進入Maven  Spring 3
於

沒有留言:

張貼留言